u Calculate e
http://acm.zju.edu.cn/show_problem.php?pid=1113
Time limit: 1 Seconds
Memory limit: 32768K
1. Background
A simple mathematical formula for e is
latex($$e=\sum_{i=0}^n\frac{1}{n!}$$)
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
2. Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
3. Sample Output
n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333
Problem Source: Greater New York 2000
AC的代码:
#include<iostream> using namespace std;
int main() {
- long double t1=6, e=2.5; int n;
cout<<"n"<<" "<<"e"<<endl;
cout<<"-
"<<endl;
cout<<0<<" "<<1<<endl; cout<<1<<" "<<2<<endl; cout<<2<<" "<<2.5<<endl;
for (n=3;n<10;n++) {
- e+=1/t1; t1*=(n+1); cout.precision(9); cout.setf(ios::fixed);
cout<<n<<" "<<e<<endl;
}
洪峰