1 #include <iostream>
   2 using namespace std;
   3 int f(int n) {
   4     if(n>=50025002)
   5         return n-5;
   6     else
   7         return f(f(n+2005));
   8 }
   9 int main() {
  10     int n;
  11     while(cin>>n)
  12         cout << f(n);
  13 }

C++小程序 (2010-01-02 21:55:08由czk编辑)

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