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5.1 Pointers and Addresses 指针与地址
Let us begin with a simplified picture of how memory is organized. A typical machine has an array of consecutively numbered or addressed memory cells that may be manipulated individually or in contiguous groups. One common situation is that any byte can be a char, a pair of one-byte cells can be treated as a short integer, and four adjacent bytes form a long. A pointer is a group of cells (often two or four) that can hold an address. So if c is a char and p is a pointer that points to it, we could represent the situation this way:
首先,我们通过一个简单的示意图来说明内存是如何组织的。通常机器都有一系列连续编号或编址的存储单元,这些存储单元可以单个进行操纵,也可以以连续成组的方式操纵。通常情况下,机器的一个字节可以存放一个char类型的数据,两个相邻的字节存储单元可以存储一个short(短整型)类型的数据,而4个相邻的字节存储单元可存储一个long(长整型)类型的数据。指针是能够存放一个地址的一组存储单元(通常是两个或4个字节)。因此,如果c的类型是char,并且p是指向c的指针,则可用图5-1表示它们之间的关系:
The unary operator & gives the address of an object, so the statement
p = &c;
assigns the address of c to the variable p, and p is said to "point to" c. The & operator only applies to objects in memory: variables and array elements. It cannot be applied to expressions, constants, or register variables.
一元运算符&可用于取一个对象的地址,因此,下列语句:
p = &c;
将把c的地址赋值给变量p,我们称p为“指向”c的指针。地址运算符&只能应用于内存中的对象,即变量与数组元素。它不能作用与表达式、常量或register类型的变量。
The unary operator * is the indirection or dereferencing operator; when applied to a pointer, it accesses the object the pointer points to. Suppose that x and y are integers and ip is a pointer to int. This artificial sequence shows how to declare a pointer and how to use & and *:
一元运算符*是间接寻址或间接引用运算符。当它作用于指针时,将访问指针所指向的对象。我们在这里假定x与y是整数,而ip是指向int类型的指针。下面的代码段说明了如何在程序中声明指针以及如何使用运算符&和*:
The declaration of x, y, and z are what we've seen all along. The declaration of the pointer ip,
1 int *ip;
is intended as a mnemonic; it says that the expression *ip is an int. The syntax of the declaration for a variable mimics the syntax of expressions in which the variable might appear. This reasoning applies to function declarations as well. For example,
1 double *dp, atof(char *);
says that in an expression *dp and atof(s) have values of double, and that the argument of atof is a pointer to char.
变量x、y与z的声明方式我们已经在前面的章节中见到过。我们来看指针ip的声明,如下所示:
1 int *ip;
这样声明是为了便于记忆。该声明语句表明表达式*ip的结果是int类型。这种声明变量的语法与声明该变量所在表达式的语法类似。同样的原因,对函数的声明也可以采用这种方式。例如,声明
1 double *dp, atof(char *);
表明,在表达式中,*dp和atof(s)的值都是double类型,且atof的参数是一个指向char类型的指针。
You should also note the implication that a pointer is constrained to point to a particular kind of object: every pointer points to a specific data type. (There is one exception: a "pointer to void" is used to hold any type of pointer but cannot be dereferenced itself. We'll come back to it in Section 5.11.)
我们应该注意,指针只能指向某种特定类型的对象,也就是说,每个指针都必须指向某种特定的数据类型。(一个例外情况是指向void类型的指针可以存放指向任何类型的指针,但它不能间接引用其自身。我们将在5.11节中详细讨论该问题)。
If ip points to the integer x, then *ip can occur in any context where x could, so
1 *ip = *ip + 10;
increments *ip by 10.
如果指针ip指向整型变量x,那么在x可以出现的任何上下文中都可以使用*ip,因此,语句
1 *ip = *ip + 10;
将把*ip的值增加10。
The unary operators * and & bind more tightly than arithmetic operators, so the assignment
1 y = *ip + 1
takes whatever ip points at, adds 1, and assigns the result to y, while
1 *ip += 1
increments what ip points to, as do
1 ++*ip
and
1 (*ip)++
The parentheses are necessary in this last example; without them, the expression would increment ip instead of what it points to, because unary operators like * and ++ associate right to left.
一元运算符*和&的优先级比算术运算符的优先级高,因此,赋值语句
1 y = *ip + 1
将把*ip指向的对象的值取出并加1,然后再将结果赋值给y,而下列赋值语句:
1 *ip += 1
则将ip指向的对象的值加1,它等同于
1 ++*ip
或
1 (*ip)++
语句的执行结果。语句(*ip)++中的圆括号是必需的,否则,该表达式将对ip进行加一运算,而不是对ip指向的对象进行加一运算,这是因为,类似于*和++这样的一元运算符遵循从右至左的结合顺序。
Finally, since pointers are variables, they can be used without dereferencing. For example, if iq is another pointer to int,
1 iq = ip
copies the contents of ip into iq, thus making iq point to whatever ip pointed to.
最后说明一点,出于指针也是变量,所以在程序中可以直接使用,而不必通过间接引用的方法使用。例如,如果iq是另一个指向整型的指针,那么语句
1 iq = ip
将把ip中的值拷贝到iq中,这样,指针iq也将指向ip指向的对象。