An Easy Task
http://acm.hdu.edu.cn/showproblem.php?pid=1076
1
2 #include
3
4 int isleap(int y) {
5 return y%400 == 0 || y%4 == 0 && y%100 != 0;
6 }
7
8 int main() {
9 int t;
10 scanf("%d", &t);
11 while(t--) {
12 int y, n;
13 scanf("%d%d", &y, &n);
14 while(n > 0)
15 if(isleap(y++))
16 n--;
17 printf("%d\n", y-1);
18 }
19 }
hdu1076 (2008-06-01 14:39:59由czk编辑)