# Determine the Price

Time limit: 1 Seconds

Memory limit: 32768K

For the manager of a theatre, setting the price of a ticket is a rather delicate matter. Suppose that a theatre has n (<= 1000000) seats, and that if you give away the tickets for free, all the seats will be taken. After some sort of investigation, it is estimated that for every p yuans of increase of the ticket price, the theatre will lose m audiences. But the audiences will not leave until the ticket price jumps up a complete step of p yuans. For example, if given p=1.00 and m=10, no audience will be lost if the price is set to be 0.99 yuans, and 10 will be lost if the price is 1.99 yuans. It costs R yuans for the theatre to run each show, and S yuans to serve each of the audiences during each show. Now your job is to write a program to maximize the total revenue of each show for the theatre.

## 1. Input

The first line of input contains a positive integer N (< 10000), then followed by N test cases.

Each test case consists of 5 positive numbers in a line, n, p, m, R, S which are all defined in the problem.

## 2. Output

For each test case, print the optimal price of a ticket, the total number of audiences to sit in the theatre with that price set, and the maximum revenue, in the format illustrated by the sample output.

Note: the unit of price is RMB yuan, and a price must be rounded off to 2 decimal places. There must be one blank line between two test cases, but no extra line at the end of output.

## 3. Sample Input

2 1000 0.10 10 1000 2.00 100 0.50 2 500 2.0

## 4. Sample Output

price = 6.09 audiences = 400 revenue = 636.00 price = 13.99 audiences = 46 revenue = 51.54

Problem Source: Zhejiang University Local Contest 2002